Question

Please help!!!!! 

1) Use the quadratic formula to solve the equation.

4x^2−10x+5=0

Enter your answers, in simplified radical form, in the boxes.

x=
or x=

2) What are the zeros of the function f(x) =x^2+7x−18?

Enter your answers in the boxes.

The zeros of f(x) are ______ and _______

The photo is a completly diffrent question 
.

Answer 1

part 1) Use the quadratic formula to solve the equation.

4x^2−10x+5=0

we know that
the quadratic formula is

`x=[-b (+/-) \sqrt{b^(2) -4ac}]/ 2a`
in this problem
a=4
b=-10
c=5


`x=[10 (+/-) \sqrt{10^(2) -4*(4)*(5)}]/(2*4)\\ x=[10(+/-) √(20)]/8 \\ x1=[10+ √(20)]/8 \\ x2=(10- √(20)]/8`

the answer Part 1) is


`x1=(5+ √(5))/4 \\ x2=(5- √(5) )/4`

Part 2) What are the zeros of the function f(x) =x^2+7x−18?

we have
f(x)=x²+7x-18
equals to zero the function
x²+7x-18=0
Group terms that contain the same variable, and move the constant to the opposite side of the equationx²+7x=18
Complete the square. Remember to balance the equation by adding the same constants to each side
x²+7x+12.25=18+12.25
Rewrite as perfect squares(x+3.5)²=30.25-----> square root----> (+/-)[x+3.5]=5.5
(+)[x+3.5]=5.5---> x=5.5-3.5----> x=2
(-)[x+3.5]=5.5----> x=-9
the answer part 2) isthe zero of the function arex=2 and x=-9
Part 3) question of the picture
`(2 x^(2) +4x-8)-(4 x^(2) -x+1) \\ (2 x^(2) -4 x^(2) )+(4x+x)+(-8-1) \\ -2 x^(2) +5x-9 \\ standart form \\ a x^(2) +bx+c=0 \\ -2 x^(2) +5x-9=0`