Answer:
![6764\pi](https://img.qammunity.org/2019/formulas/mathematics/high-school/ea7ycfdp6djuntj4g8dris9ae941pnccye.png)
Explanation:
3876
![\pi](https://img.qammunity.org/2019/formulas/mathematics/middle-school/w2mw2141nk3383oncfx010frgx49xcj0c8.png)
Explanation:
The Surface area of the Cylinder is given by the formula
![SA=2\pi r^2+2\pi rh](https://img.qammunity.org/2019/formulas/mathematics/high-school/fxo10q4er5yomtioexoy4uv5bua92fmucd.png)
Here we are given with the value of radius and the height as 38 mm and 51 mm.
Now we put the values of r and h in the above formula and evaluate he Surface Area
![SA= 2\pi*38^(2)+2\pi*38*51\\SA=2888\pi+2\pi*1938\\SA=2888\pi+3876\pi\\6764\pi](https://img.qammunity.org/2019/formulas/mathematics/high-school/y9al51ebvg2mkxpmb16grxjpp6okra8f09.png)
Hence the Surface area is
![SA=6764\pi](https://img.qammunity.org/2019/formulas/mathematics/high-school/vdabbonedgxjhbaml17v6xmip2arw11kq8.png)