Answer with explanation:
The given series is
![(1)/(5)+(1)/(15)+(1)/(45)+(1)/(81)+.....](https://img.qammunity.org/2019/formulas/mathematics/high-school/k9buenlwtbulejpwkex0unyn9mmlze51t1.png)
The given series is a geometric sequence,whose common ratio is equal to
![R=\frac{2^(nd)\text{term}}{1^st \text{term}}\\\\R=((1)/(15))/((1)/(5))\\\\R=(5)/(15)\\\\R=(1)/(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ovh2lbtshi7i5dzdyyv49ftvvfj0fh45ky.png)
Sum to Infinity is given by the formula
![S_(\infty)=\frac{\text{First term}}{1-\text{Common ratio}} \text{or}\frac{\text{First term}}{\text{Common ratio}-1} \\\\S_(\infty)=((1)/(5))/(1-(1)/(3))\\\\S_(\infty)=((1)/(5))/((2)/(3))\\\\S_(\infty)=(3)/(10)](https://img.qammunity.org/2019/formulas/mathematics/high-school/vf5btds753ntfi1i0fw7esz8ctoh24kgfi.png)
As the sum of series is Finite, that is having a single value, so the series is Convergent.
If it has more than one sum, it would have been Divergent.
Option D: It converges; it has a sum.