Question

Write the equation of a parabola with focus of (1,-2) and vertex at (9,-2).

Answer 1

(y+2)^2=32(x-9)

Explanation:

I know it's late, but for anyone who needs it!

Answer 2

Because the y-coordinates are the same in this parabola, it is a sideways-opening parabola, or one of the form
`(y-k) ^(2)=4p(x-h)` where p is the distance between the focus and the vertex. Our distance is 9-1 = 8, and the (h, k) of our vertex is (9, -2), therefore, the equation is
`(y+2) ^(2) =32(x-9)`. Not sure how much you need to simplify this, but that's the standard form.