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A polyhedron has 8 vertices and 14 edges. How many faces must it have?
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2 votes
A polyhedron has 8 vertices and 14 edges. How many faces must it have?

User Samu Lang
by
5.3k points

1 Answer

2 votes
we know that
The Euler's formula state that,
the number of vertices, minus the number of edges, plus the number of faces, is equal to two
V - E + F = 2
clear F
F=2-V+E
in this problem
V=8
E=14
F=?
so
F=2-8+14
F=8

the answer is
8 faces
User Abax
by
4.8k points
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