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I am not exactly sure how to do this. Any pointers?

I am not exactly sure how to do this. Any pointers?-example-1

1 Answer

4 votes
<BFD= 122 degrees.

Since we know that <CFD = 55 degrees, then we can simply do <BFD- <CFD (122-55) in order to solve for <BFC, which is 67 degrees.

In addition, we know that <BFE = 180 degrees. This means that <BFC + <CFD + <DFE = <BFE. <BFE- (<BFC + <CFD) = <DFE. 180-55-67= <DFE. <DFE= 58 degrees. <DFE=<AFB so <AFB would be 58 degrees.

<CFE would just be <CFD + <DFE or (55+58) = <CFE= 113.

Finally, <AFE= <BFD. <AFE = 122.




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