The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.
Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter
. Thus, from the given information we can conclude that:
![(Powder Weight)/(Water Weight)=(3)/(2)=(120)/(x)](https://img.qammunity.org/2019/formulas/mathematics/college/xat4lt22eeeq4ajzgai8w26y1402jw9e7l.png)
![\therefore (3)/(2)=(120)/(x)](https://img.qammunity.org/2019/formulas/mathematics/college/uxwtaycbrbpcgtpve1dnh4t75r34k5ptmx.png)
Cross-multiplying we get:
![3x=240](https://img.qammunity.org/2019/formulas/mathematics/college/5c4z8jc9y583klhmsezkeg93cbo0z9ckah.png)
grams.
Thus, the amount of water in grams in that Kool-aide is 80 grams.