189k views
1 vote
Kool-aide is made from flavored powder and water, with the ratio of powder to water 3:2 based on weight. If 120g of flavored powder are needed for a certain amount of Kool-aide, how much water will be needed for this amount?

User Ivanivan
by
7.7k points

1 Answer

3 votes

The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.

Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter
x. Thus, from the given information we can conclude that:


(Powder Weight)/(Water Weight)=(3)/(2)=(120)/(x)


\therefore (3)/(2)=(120)/(x)

Cross-multiplying we get:


3x=240


\therefore x=(240)/(3)=80 grams.

Thus, the amount of water in grams in that Kool-aide is 80 grams.

User YASH THUMAR
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories