Question

PLEASE I BEG YOU, HELP ME!!!!!!!! Find the rate of change of the function h(x) = 2^x on the interval 2 ≤ x ≤ 4. The rate of change is what?

Answer 1

rate of change=

`(y2 - y1)/(x2 - x1)`
y2 and x2 being the coordinates of the point furthest from the (0,0) and x1 and y1 being the nearest

so if x1=2 then
h(x)= 2^2 = 4

and if x2=4 then
h(x)= 2^4=16

so rate of change is

`(16 - 4)/(4 - 2) = (12)/(2 ) = 6`