(8n+1)(6n-3) please solve in quadratic formula

asked Aug 10, 2019 227k views

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4 votes

Use the distributive property.

$(8n+1)(6n-3)=(8n)(6n)+(8n)(-3)+(1)(6n)+(1)(-3)\\\\=48n^2-24n+6n-3=48n^2-18n-3$

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