Answer: The correct option is (C)
![4\sqrt2.](https://img.qammunity.org/2019/formulas/mathematics/college/orf8kirclqll01zkvh28olo8ww640ruob5.png)
Step-by-step explanation: We are given to find the length of side 's' of the square shown in the figure.
We know that
all the four sides of a square are equal in length and all the four angles are right angles.
So, each of the two equal parts of the square form a right-angled triangle with hypotenuse as the diagonal.
Therefore, using Pythagoras theorem in one of the right-triangles, we get
![s^2+s^2=8^2\\\\\Rightarrow 2s^2=64\\\\\Rightarrow s^2=32\\\\\Rightarrow s=\pm√(32)\\\\\Rightarrow s=\pm4\sqrt2.](https://img.qammunity.org/2019/formulas/mathematics/college/g9w7qr77qzbi36xn4eepvxvr8csb3s7vgb.png)
Since the length of a side of a square cannot be negative, so we get
![s=4\sqrt2~\textup{units}.](https://img.qammunity.org/2019/formulas/mathematics/college/ggb8g1a09vs715i4jb4zd6v27d6ptwar4f.png)
Option (C) is CORRECT.