well, a line parallel to that one on the graph, will have the same exact slope, wait just a second, what the dickens is the slope of that one on the graph anyway?
well, let's pick two points off of it hmmmmm let's use those given ones, (-3,3) and (-2,1),
![\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -3 &,& 3~) % (c,d) &&(~ -2 &,& 1~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-3}{-2-(-3)} \\\\\\ \cfrac{1-3}{-2+3}\implies \cfrac{-2}{1}\implies -2]()
alrity, so the graphed line has a slope of -2, then our parallel line will also have a slope of -2, and we also know that it passes through 4,1,
![\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ 4 &,& 1~) \end{array} \\\\\\ % slope = m slope = m\implies -2 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-2(x-4)]()