Question

A student increases the temperature of a 200 cm3 balloon from 33degrees C to 47 degrease C. What will the new volume of the ballon be?

Answer 1

The answer is 209.15cm3

The volume is directly related to the temperature of a gas. You can solve this question using Charles' law, but remember to convert the temperature from Celcius to Kelvin.

V1/T1= V2/T2
200 cm3/ (33+273K)= V2/(47+273K)
V2= 200cm3 * 320/306= 209.15cm3