What is the Ph of a 3.9* 10^-8 M OH- solution

asked Apr 21, 2019 159k views

0 votes

5.5k points

Please log in or register to add a comment.

3 votes

Answer: 6.59

Step-by-step explanation:

Mzyrc answered Apr 22, 2019

by Mzyrc

5.7k points

2 votes

Answer:

pH = 6.59

Step-by-step explanation:

pOH = -log(3.9 x 10^-8) = 7.41

pH = 14 - pOH = 14 - 7.41 = 6.59

Brock Boland answered Apr 25, 2019

6.7k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.6m answers