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2 votes
Given that x is an integer such that
\x√(x)-5x-9√(x)=35[, find x.

2 Answers

3 votes
I have done this several times and do not find that x is an integer. I get an imaginary number. Crazy as it seems, here's what I got all 3 times I did this:
-(286)/(50) +/- (16i √(159) )/(50). That is definitely NOT an integer!

User Shaze
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6.9k points
3 votes
There appears to be a mistake in the LaTeX, so that the equation is supposed to be

x√(x)-5x-9√(x)=35
If we let z=√x, then this is

z^(3)-5z^(2)-9z-35=0

By Descartes' rule of signs, this will have one positive real root. The rational root theorem says it will be one of 1, 5, 7, or 35. It is actually z=7. The corresponding value of x is
x = z² = 7² = 49.

A graphing calculator finds the solution to the original equation easily. (I find it useful to put it in the form f(x)=0.)

x = 49
Given that x is an integer such that \x√(x)-5x-9√(x)=35[, find x.-example-1
User Geoff Bennett
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6.7k points
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