1 Answer

Phu Ngo · Answer 1 · 2019-03-12T13:36:24+0000

The answer is
$8\sqrt2$

Here we have a radical that could be simplified further. I will show you how it's done with these steps:

$\sqrt128$
From here, you need to find a factor of 128 that is a perfect square, like 4:

$\sqrt(4 * 32)$

$= \sqrt4 * \sqrt32$

$= 2 * \sqrt32$

$= 2\sqrt32$
But we're not done here since
$\sqrt32$ can be simplified further. We know that 16 is a factor of 32 that is a perfect square.

$2\sqrt32$

$= 2\sqrt(16*2)$

$= 2*\sqrt16 * \sqrt2$

$= 2 * 4 * \sqrt2$

$= 8 * \sqrt2$

$= 8\sqrt2$

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