Question

PC bisects BPD find M
Is this right?

Answer 1

yes that is correct...to my calculations it is correct! good job!

Answer 2

Solving the problem in the following way

`\overrightarrow{PC}` bisects ∠BPD.

Then, ∠BPC=∠DPC-----(1)

AD is a line , on which ray PB and PC lies.

→∠APB+∠BPC+∠CPD=180°----By linear pair axiom

→124°+∠DPC+∠DPC=180°------[Using 1]

→124°+2∠DPC=180°

→∠DPC=180°-124°

→2∠DPC=56°

Dividing both sides by,2 we get

→∠DPC=28°