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Write an equation with amplitude 2, period (T) pi/2, phase shift (ø) - pi/4, and a midline y=-3.

Im mostly struggling with the period.

User Markus Hi
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2 Answers

3 votes
The amplitude is 2, so A = 2 (see note 1 below)

The period is T = pi/2 which means
B = 2pi/T
B = 2pi/(pi/2)
B = 2pi*(2/pi)
B = 4

The phase shift is C = pi/4
The midline is y = -3 indicating that D = -3

Put this all together and we go from this (see note 2)
y = A*sin(B(x-C)) + D
to this
y = 2*sin(4(x-pi/4)) + (-3)
and that simplifies to
y = 2sin(4x-pi) - 3
which is one way to write the final simplified answer (see note 3)

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Extra Stuff:
Note 1: The value of A can be A = -2. Recall that the amplitude is equal to |A|. So If A = -2, then |A| = |-2| = 2. The amplitude is the vertical distance from the midline to the peak or valley. Distance can't be negative. To make things simple, I went with A = 2.

Note 2: The general formula involving sine can be replaced with cosine instead. The cosine function is basically sine but a phase shift of it (it has the same shape and pattern, but has been moved over). You cannot use tangent as that is a completely different class of function.

Note 3: I distributed the 4 through to the (x-pi/4) to get 4x-pi. Your teacher or book may want you to keep things factored and not distribute. If so, then the answer would be y = 2sin(4(x-pi/4)) - 3. That is of course you went with using sine instead of cosine. The benefit of not distributing is that we can more easily see what the phase shift is.
User Manouchka
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7 votes

Sure thing! Here's how you can write this equation:

First, let's look at the general form of a sine function:

y = A * sin(B*(x - ø)) + D

Where:
- A is the amplitude
- B = 2pi / T
- ø is the phase shift
- D is the midline

The amplitude tells us the peak deviation of the function from its midline, so here it will be 2.

The period is pi/2, so that means B, which equals 2pi divided by the period, will be 2pi/(pi/2) = 4.

The phase shift is negative pi/4. This value gets subtracted from x inside the sine function, effectively shifting the graph to the right by pi/4.

The midline of the graph is -3. This vertical shift is represented by D, which is -3.

Now insert these into the general form:

y = 2 * sin(4*(x - (-pi/4))) - 3

Or simplifying:

y = 2 * sin(4x + pi) - 3

This equation represents a sine curve with an amplitude of 2, a period of pi/2, shifted to the right by pi/4, and shifted downward by 3 units.

User Richs
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