Question

I NEED ASAP!

Curious Carl's chemistry teacher asked him to make a sugar solution. Carl dissolved 50.0 grams of sucrose (C12H22O11, molar mass 342.3 g/mol) in 1.00 L of water. If molarity = moles/liter, what is the molarity of Carl's sugar solution?
A)0.008m
B)0.146m
C)0.190m
D)0.342m

Answer 1

B 0.146m
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Answer 2

Answer:The correct answer is option B.

Step-by-step explanation:

Mass of surcose dissolved = 50.0 g

volume of water = 1 L

Molarity=
`\frac{\text{Mass of sucrose}}{\text{molar mass of sucrose}* \text{volume of solvent in L}}`

`Molarity=(50.0 g)/(342.3 g/mol* 1 L)=0.1460 mol/L`

Hence ,the correct answer is option B.