Question

The two dot plots below show the heights of some sixth graders and some seventh graders:

The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 0.6. Approximately how many times the variability in the heights of the seventh graders is the variability in the heights of the sixth graders? (Round all values to the tenths place.)

0.3
2.0
1.2
1.7

Answer 1

2.0 because if you divide 1.2 by 0.6 it equals 2.0

Answer 2

Answer: The variability in the heights of the sixth graders is 2 times the variability in the height of the seventh graders.

Explanation:

Since we have given tha t

Mean absolute deviation for the first set of data = 1.2

Mean absolute deviation for the second set of data = 0.6

We need to find the number of times the variability in the height of the seventh grade is the variability in the heights of the sixth graders.

So, our expression becomes

`(MAD\ of Seventh\ greade)/(MAD\ of\ sixth\ grade)\\\\=(1.2)/(0.6)\\\\=2`

Hence, the variability in the heights of the sixth graders is 2 times the variability in the height of the seventh graders.