Solve for x in the equation x^2-8x+41=0

asked Mar 14, 2019 219k views

1 vote

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3 votes

x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2

x = ( 8 + sqrt (-100) / 2 and (8 - sqrt(-100) / 2

4 +or- 5i

5.7k points

1 vote

x=28+10ı,28−10ı

x=4+5ı,4−5ı

hope this helps the bottom one is the answer :)

Scott Veirs answered Mar 20, 2019

5.2k points

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