Your question isn't quite formatted correctly to be a quadratic equation as it has no variable for the "a" and "b" terms but I'll just insert them and hopefully it will match what you're asking.
Let x be our variable.
36x² - 46x - 22
The quadratic formula for a quadratic equation in the format ax² + bx + c = 0 is:
![x = \frac{- b +/- \sqrt{b^(2) - 4ac} }{2a}](https://img.qammunity.org/2019/formulas/mathematics/high-school/yo5jl9d3hh0eqrn01qfqvwv4k0eselr0tt.png)
Now we just insert our terms to the formula:
![x = \frac{46 +/- \sqrt{(-46)^(2) - 4(36)(-22)} }{2(36)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/6b1d1mez9pqx7o0iw0dzt8mign7vyryvv4.png)
And now we solve:
![x = (46 +/- √(2116 + 3168))/(72)](https://img.qammunity.org/2019/formulas/mathematics/high-school/vnwigin42rcvuy8pm9pcbrad4l1dz93ek1.png)
![x = (46 +/- √(5284))/(72)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ndjs4rfh7k91zs93f05337y6xpuwsqftyi.png)
![x = (46 +/- 2√(1321))/(72)](https://img.qammunity.org/2019/formulas/mathematics/high-school/cpte099ra04awasfgnor6v0msk0lzr04f0.png)
Your final answers when you simplify:
![x = (23 + √(1321) )/(36)](https://img.qammunity.org/2019/formulas/mathematics/high-school/t9g1hq7yoxc2l6isnbnzy0fjxjpz6z4nry.png)
and
![x = (23 - √(1321))/(36)](https://img.qammunity.org/2019/formulas/mathematics/high-school/jrdzfzzkgwkg01al1ld3nse4b11wk7zvla.png)