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Please help question #14!!!
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Please help question #14!!!

Please help question #14!!!-example-1
User Avladov
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\text{The domain:\\a+3\\eq0\ \wedge\ a-2\\eq0\\a\\eq-3\ \wedge\ a\\eq2


(5)/(a+3)=(3)/(a-2)\ \ \ \ |\text{cross multiply}\\\\5(a-2)=3(a+3)\\\\5a-10=3a+9\ \ \ |+10\\\\5a=3a+19\ \ \ \ |-3a\\\\2a=19\ \ \ \ |:2\\\\a=9(1)/(2)\\\\Answer:\ B.\ a=9(1)/(2)
User Jonathon Ashworth
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