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PLEASE SOMEBODY HELP ME WITH THIS

PLEASE SOMEBODY HELP ME WITH THIS-example-1
User Techniquab
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The ice cream cone consists of a semi-circle with a diameter of 10 cm and a triangle with a base of 10 cm and height of 12 cm.

The area of a semi-circle is half the area of a full circle, so we can find it by using:


A= (1)/(2) \pi r^2

If the diameter of the circle is 10 cm, then the radius is 5 cm. Plug in the known values:


A= (1)/(2) \pi (5)^2


A = 12.5 \pi or about 39.25

The area of a triangle is:


A = (1)/(2) bh

So we can plug in the known values to find the area to be:


A= (1)/(2) (10)(12)=60

When we add the areas of the two sections together, we get an exact answer of:

(60 + 12.5pi) cm^2

or about 99.25 cm^2
User Taurean
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