Answer:
f(x) = 4 for the values 2 and -2.
Explanation:
Given
y = { x+6 x < -2
x² -2 ≤ x ≤ 3
3x+1 x > 3 }
To determine
For which x-values is f(x) = 4
It is clear that:
The portion of the function f(x) = x² has the interval -2 ≤ x ≤ 3
Now, if we enter x = 2 or x = -2 in f(x) = x² from the interval -2 ≤ x ≤ 3 we get the output 4.
i.e.
at x = -2,
f(-2) = (-2)² = 4
also
at x = 2,
f(2) = (2)² = 4
Therefore, f(x) = 4 for the values 2 and -2.