Question

In ​ Quadrilateral ABCD, AB∥CD and m∠2=27.

What is m∠5?

Enter your answer in the box.

Answer 1

Quadrilateral ABCD, AB∥CD
m∠2=27 so m<5 = 27 (alternate interior angles are equal)

Answer
m∠5=27

Answer 2

Answer:
`\angle5` = 27°

Step-by-step explanation:

Given: ABCD is a Quadrilateral and AB is parallel to CD and
`\angle 2`=27 degree

We have to find out:
`\angle 5`

since, AB is parallel to CD , and according to the properties of parallel lines If two parallel lines are cut by a transversal line then the alternative interior angles made by that transerversal are always equal.

here BD makes the transversal line for parallel lines AB and CD. and
`\angle 2` and
`\angle 5` are interior angles of lines CD and AB respectively. And these angle are alternative to each other.

Thus they must have the equal values. This implies if
`\angle 2` = 27° then
`\angle 5`= 27°