Question

write the standard form of the equation of the circle with radius and center (h,k). r =4; (h,k) = (-2,-3) nee help please answer.

Answer 1

The standard form of the circle equation is:

`{(x - h)}^(2) + {(y - k)}^(2) = {r}^(2)`
In this problem,
r = 4
h = -2
k = -3

Therefore, we just plug in the numbers and simplify:

`{(x - ( - 2))}^(2) + {(y - ( - 3))}^(2) = {(4)}^(2) \\ {(x + 2)}^(2) + {(y + 3)}^(2) = 16`
The correct answer is A

Answer 2

The equation of the circle is written as (x-h)² + (y-k)² = r²

With the given center and radius the equation will be

(x + 2)² + (y + 3)² = 16

The answer is A

Hope this helps :)