Question

Ten grams of a gas occupies 12.5 liters at a pressure of 42.0 cm Hg. What is the volume when the pressure has increased to 75.0 cm Hg?

Answer 1

Based on the question, it is evident that the question is based on Boyle's Law which we will use to find the answer necessary.

Now, Boyle's Equation: P₁V₁ = P₂V₂

V₂ = P₁V₁ ÷ P₂

∴ V₂ = (12.5L × 42.0 cm · Hg) ÷ 75 cm · Hg

⇒ V₂ = 7 L

Thus, the volume when the pressure has increased to 75.0 cm Hg is 7 Litres.