The graph of the path of the swooping bird is shown in figure below. The general form of the hyperbola equation is given by:
![(y^(2))/(a^(2))-(x^(2))/(b^(2))=1](https://img.qammunity.org/2019/formulas/mathematics/high-school/svdmlyngvz7ng3vrgrv0qf5awawly85le0.png)
So we can order the equation of the problem by multiplying it by the following term:
![(1)/(49000)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y3ivtam1a11iprqlfpcl3niv66mhro8l10.png)
Therefore:
![(y^(2))/(35^(2))-(x^(2))/(2^(2))=1](https://img.qammunity.org/2019/formulas/mathematics/high-school/x93d4vuov09y17u7x0v8nwpnmy5fhpgcmb.png)
∴
![(y^(2))/(1225)-(x^(2))/(4)=1](https://img.qammunity.org/2019/formulas/mathematics/high-school/plw13cb7p7ni2snr7movkdgdna50ptp2bx.png)
Given that the origin lies at ground level, t
he bird is closest to the ground at the vertices of the parable, that is, when x = 0 (this will give us two solutions, but we will take the positive value because the bird flight over the air)
![(y^(2))/(1225)-(0^(2))/(4)=1 \rightarrow y=√(1225) \rightarrow \boxed{height=35m}](https://img.qammunity.org/2019/formulas/mathematics/high-school/pa9ghb7wkhgt35vn5kofdke6jwmckyjdby.png)