Question

Find the solution set. The solution set for 7q^2 − 28 = 0 is { }. (Separate the solutions with a comma)

Answer 1

Hi there! The answer is {-2, 2}
Let's solve this problem step by step!


`7 {q}^(2) - 28 = 0`
First add 28 to both sides.


`7 {q}^(2) = 28`
Now divide both sides by 7.


`{q}^(2) = 4`
Take the root of both sides, and the negative root of 4.


`q = √(4) \: \: or \: \: q = - √(4) \\ q = 2 \: \: \: \: \: \: or \: \: q = - 2`
Therefore the solution set to this equation is {-2, 2}

~ Hope this helps you!