Question

Carbon disulfide burns with oxygen to form carbon dioxide and sulfur dioxide in the following manner: CS2 + 3O2 → CO2 + 2SO2 What is the volume of sulfur dioxide (SO2 gas), formed when 2 moles of carbon disulfide (CS2) are burned? The reaction is taking place at STP.

5.6 L
22.4 L
89.6 L
44.8 L

Answer 1

The balanced chemical reaction is written as:

CS2 + 3 O2 CO2 + 2 SO2

We are given the amount of carbon disulfide to be used for this reaction. We us this amount as the starting point for the calculations.

2.0 mol CS2 (2 mol SO2/ 1 mol CS2) (22.4 L/1 mol) = 89.6 L

So your answer is going to be 89.6 L (C)

Answer 2

Answer:89.6L

Step-by-step explanation:

From the balanced stoichiometric equation, we see that 1 mole of carbon disulphide is needed to produce 2 moles of sulphur dioxide. Since 1 mole of a gas occupies 22.4L, we work with that as shown in the image. Hence we obtain the volume of sulphuy dioxide produced by two moles of carbon disulphide