Question

4^x-3=6 please help

Answer 1

`4^(x+3)=6\ \ \ \ |\log_4\\\\\log_44^(x+3)=\log_46\ \ \ |\text{Use}\ \log_ab^n=n\log_ab\\\\(x+3)\log_44=\log_46\ \ \ \ |\text{Use}\ \log_aa=1\\\\x+3=\log_46\ \ \ |-3\\\\x=\log_46-3\ \ \ \ |\text{Use}\ b=\log_aa^b\\\\x=\log_46-\log_44^3\\\\x=\log_46-\log_464\ \ \ |\text{Use}\ \log_ab-\log_ac=\log_a(b)/(c)\\\\x=\log_4(6)/(64)\\\\x=\log_4(3)/(32)`