Question

If a gas in a closed container is pressurized from 9.71 atmospheres to 16.0 atmospheres and its original temperature was 25.0oC, what would the final temperature of the gas be?

Answer 1

Givens
P1 = 16.0 atm
P = 9.71
T = 25.0o C = 273 + 25 = 298o K
T1 = ???

Formula
P / T = P1 / T1

Sub and Solve
9.71 / 298 = 16.0 / T1 Cross Multiply
9.71 * T1 = 298 * 16 Divide by 9.71
T1 = 298 * 16 / 9.71
T1 = 491.0 oK That's Pretty warm.

C = 491.0 = 273
C = 218.0 <<<<<<<<<<<<<<<< Answer in Degrees Centigrade.