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Hydrogen gas and oxygen gas combine to form water. How many grams of oxygen are needed to react with 45.7 grams of hydrogen ?

1 Answer

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The balanced equation:
2 H₂ + O₂ → 2 H₂O

moles of Hydrogen = mass of hydrogen ÷ molar mass of hydrogen
= 45.7 g ÷ 2 g/mol
= 22.85 mol

Now, the mole ratio of O₂ : H₂ is 1 : 2
which means that there are two times as much moles of H₂ as O₂ taking
part in the reaction

Thus since moles of H₂ = 22.85 mol
then moles of O₂ = 22.85 ÷ 2 = 11.425 mol

Mass of O₂ = moles of O₂ × molar mass of O₂

= 11.425 mol × 32 g/mol

= 365.6 g

grams of oxygen are needed to react with 45.7 grams of hydrogen is 365.6g
User Ammar Bozorgvar
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