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Evaluate the expression: 23C3

User Yisan
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This looks like
(23!)/((23-3)!*3!). Simplify this down to
(23*22*21)/(1*2*3). This simplification gives you that 23C3 = 1771. You would have gotten the same result had you drawn out Pascal's Triangle to 24 rows and gone in 3 in that row. That would have been your 1771. Whichever is easiest is the way I recommend.
User David Narayan
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