This looks like
![(23!)/((23-3)!*3!)](https://img.qammunity.org/2019/formulas/mathematics/high-school/zasy661swnyyk1r56w0gx1eq9qtj49h2xj.png)
. Simplify this down to
![(23*22*21)/(1*2*3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/qwa5e8zhzwpo9gpmoeoe7tpl1amzezoktw.png)
. This simplification gives you that 23C3 = 1771. You would have gotten the same result had you drawn out Pascal's Triangle to 24 rows and gone in 3 in that row. That would have been your 1771. Whichever is easiest is the way I recommend.