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Prove that 2cos2x/sin2x=cotx-tanx, show every step on how to solve it

User David Pope
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2cos2x/sin2x=cotx-tanx

2cos2x/sin2x = 2(cos²x-sin²x)/(2sinx*cosx) = (2cos²x-2sin²x)/(2sinx*cosx) =

= 2cos²x/(2sinx*cosx) - 2sin²x)/(2sinx*cosx) = cos x/ sin x - sinx/cos x =
= cot x-tan x

Left side is equal to right side, so
2cos2x/sin2x=cotx-tanx is true.
User Nathan Gonzalez
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