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Cube root of - 1000p^12q^3

User Mreithub
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2 Answers

3 votes

Answer: -10p^4q

Explanation:

User Asutherland
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\bf \sqrt[3]{-1000p^(12)q^3}~~ \begin{cases} 1000=10^3\\ (-1)^3=-1\cdot -1\cdot -1\\ \qquad -1\\ p^(12)=p^(4\cdot 3)\\ \qquad (p^4)^3 \end{cases}\implies \sqrt[3]{(-1)^3(10)^3(p^4)^3q^3} \\\\\\ (-1)(10)p^4q\implies -10p^4q
User Jelmer Jellema
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