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If CG = 10, AC = 8, BC = 5 find DC 4 2√(10) 1.5
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If CG = 10, AC = 8, BC = 5 find DC
4
2√(10)
1.5

If CG = 10, AC = 8, BC = 5 find DC 4 2√(10) 1.5-example-1
User Yate
by
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1 Answer

2 votes
For secants from a common external point, the product of near and far lengths to the circle is a constant.
BC·AC = DC·GC
5·8 = DC°10
DC = 40/10
DC = 4

The appropriate choice is the first one.
4
User Daja
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8.4k points
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