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CustomCalc · Answer 1 · 2019-08-27T08:29:01+0000

The area of the base (six triangles with a base 15m and a height 7.5√3m):

$A_B=6\cdot(1)/(2)\cdot15\cdot7.5\sqrt3\approx585\ m^2$

The area of side walls (six triangles with a base 15m and a height 12m)

$A_W=6\cdot(1)/(2)\cdot15\cdot12=540\ m^2$

The surface area:

$A_B+A_W=585+540=1,125\ m^2$

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