Question

I WILL LITERALLY DO ANYTHING IF SOMEONE ANSWERS THIS QUESTION!!!!!!

Graph the system of inequalities presented here on your own paper, then use your graph to answer the following questions:

y < 4x − 2
y is greater than or equal to negative 5 over 2 times x minus 2

Part A: Describe the graph of the system, including shading and the types of lines graphed. Provide a description of the solution area. (6 points)

Part B: Is the point (−2, −2) included in the solution area for the system? Justify your answer mathematically. (4 points)

Answer 1

The answer is A and B

Explanation:

If the guy above me makes your head hurt than just do A and B

Edge 2021

Answer 2

check the picture below.

the blue inequality, overlaps the yellow one, on the right-hand-side, and where they overlap, is where the solution is, namely all those values or points.

now, is (-2,2) one of those values in that shaded area solution?

well, we can always check, is only true if that point resolves TRUE for the 1st inequality and TRUE also for the 2nd inequality, and that's how you get the shading btw, by checking their TRUE/FALSE values for each region, so let's check -2,2


`\bf (\stackrel{x}{-2},\stackrel{y}{2})\\\\ -------------------------------\\\\ 2\ \textless \ 4(-2)-2\implies 2\ \textless \ -8-2\implies 2\ \textless \ -10\leftarrow \begin{array}{llll} \textit{2 is indeed NOT}\\ \textit{smaller or lesser}\\ \textit{than 10.}~FALSE \end{array}\\\\ -------------------------------\\\\ 2\ge-\cfrac{5}{2}(-2)-2\implies 2\ge 5-2\implies 2\ge 3\leftarrow \begin{array}{llll} \textit{clearly 2 is NOT}\\ \textit{larger or greater}\\ \textit{or equal to 3.}~FALSE \end{array}`

btw, we didn't have to check the 2nd inequality, once either one of them is FALSE, the whole solution itself is false for that point, but anyway, it ended false for both, so (-2, 2) is not in the solution area, and you can even see it in the graph, (-2, 2) is to the left-side of the red line, outside the shade.