Question

How do i solve x^2+7x=3x

Answer 1

X^2 + 7x - 3x = 0
Simplify x^2 + 7x - 3x to x^2 + 4x
X^2 + 4x = 0
Factor out the common term x
X ( x + 4 ) = 0
Solve for x
X = 0,-4

Answer 2

To solve, you must make one side of the equation equal to zero. We can do this by subtracting 3x on both sides of the equation.

x^2 + 7x = 3x
- 3x -3x

x^2 + 4x = 0.

Then we substitute the equation into the quadratic equation.


`(-b+- √(b^2-4ac) )/(2a)`

Where a = 1 b = 4 and c = 0


`(-(4)+- √((4)^2-4(1)(0)) )/(2(1))`

We first solve whats inside the square root.


`(-(4)+- √(16) )/(2(1))`


`√(16) = 4`

Now we solve for -4 and 4.


`-4 - 4 = -8`

`-4+4=0`

Then divide both answer by 2


`(-8)/(2) = -4`
The division of any by zero is zero

So the answer are x = -4 and x = 0