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Which of the following is the inverse of y=12^x

User Samjudson
by
7.5k points

2 Answers

5 votes

Answer:


y = (\log x)/(\log 12)

Explanation:


y = 12^x


x = 12^y


\log x = \log 12^y


\log x = y \log 12


y \log 12 = \log x


y = (\log x)/(\log 12)

User Lee Probert
by
7.8k points
5 votes

y=12^x\ \ \ |log_(12)\\\\\log_(12)y=\log_(12)12^x\\\\\log_(12)y=x\log_(12)12\\\\x=\log_(12)y



y=12^x\to y^(-1)=\log_(12)x;\ x\in\mathbb{R^+}\to\ y^(-1)=(\log x)/(\log12);\ x\in\mathbb{R^+}\to y^(-1)=(\ln x)/(\ln 12)


Used:\\\\\log_aa=1\\\\\log_ab^n=n\log_ab\\\\\log_ab=(\log_cb)/(\log_ca)
User Panoskarajohn
by
8.0k points

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