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[07.03] what is the ph of a 6.40 × 10-3 m solution of sodium hydroxide, naoh?

User Villapalos
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1 Answer

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pOH = - log [OH]
pOH = - log (6.40 × 10-3)
pOH = 2.19

pH + pOH = 14

pH = 14 - pOH
pH = 14 - 2.19
pH = 11.8
User Hcsnemrebured
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