Question

How would the expression x^2+27 be rewritten using sum of cubes?

Answer 1

Assuming the square is not a typo, one can write



`x^2+27=(x^(2/3))^3+3^3=(x^(2/3)+3)\bigg((x^(2/3))^2-3x^(2/3)+9\bigg)`


`=(x^(2/3)+3)\bigg(x^(4/3)-3x^(2/3)+9\bigg)`