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Find the mean,variance, and standard deviation of the binomial distribution with the given values n=129 p=0.29
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Find the mean,variance, and standard deviation of the binomial distribution with the given values n=129 p=0.29

User Ken Barber
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1 Answer

5 votes
n= 129
p=0.29
then q=1-p= 1-0.29=0.71
for binomial distribution
variance=npq= 129 × 0.29 × 0.71
mean= np= 129×0.29
standard deviation= square root of variance=

√(variance) =

√(npq)
User Xgo
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