Question

A boeing 727-200 jet taking off from lansing airport accelerates from rest for 31.0 s before leaving the ground. its acceleration is 2.19 m/s2. assuming that the acceleration is constant, calculate the plane's speed at take off.

Answer 1

The answer is "151.86 mph ".

Vf = Vi +at
here vi = 0
a= 2.19m/s²
t= 31.0s

Vf = 0 + (2.19 x 31) = 67.89m/s

convert from m/s to mph

67.89m/s x 3600s/hour x 1/1609.34meters/mile

=151.86 mph