Question

25.6 grams of sodium reacts with an excess of oxygen. How many grams of sodium oxide will be produced

Answer 1

First, find the equation for
`Na+ O = NaO`

Oxygen hangs out in groups of 2 when alone so you have

`Na+ O_(2) = NaO`

Next, to balance NaO you see that Na has a charge of +1 and O has -2
You need 2 Na for the one O and now you have

`Na+ O_(2) = Na_2O`

Now you need to balance. 2 Os are on the left so make
`Na_2O`

`2Na_2O` Now you have 4 Na on the right, just make Na, 4Na

Now you have the equation
`4Na+O_2=2Na_2O`

Transfer grams to moles:
Divide the given grams (25.6) by the atomic weight of our variable (Na = 22.99)
25.6/22.99= 1.11352762 This is the number of moles you have.

Use the ratio of the amount of the element or compound to the one you want
It'll look like this
`(4Na)/(2Na_2O) = (1.11352762)/(x)`
Multiply 1.11352762 by 2 then divide by 4 leaving you with 0.55676381

Finally, multiply that by the atomic mass of
`Na_2O`
Na2 = 22.99*2 = 45.98+ O = 16 =

61.98g of
`Na_2O` is your answer