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A smaller number is less than half a large number.the larger number is 10 times 1 less than the smaller number. Let x represent the smaller number and let y represent the larger number what equation can solve this

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x<1/2y y=10(x-1)
is my reading on this.

So the first equation is x is less than one half y

second equation is y is 10 times x less 1

Were there options to choose from?
User Aurange
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