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What is the solution to the system of linear equations? {2x+4y=203x+2y=26 enter your answer in the boxes. ( , )?

2 Answers

3 votes
(3,4) is the answer, with x=3 and y=4
User Aurimas
by
5.9k points
6 votes

Answer:


(8,1)

Explanation:

We have been given a system of linear equations:


2x+4y=20...(1)


3x+2y=26...(2)

We will use substitution method to solve linear equation. From equation (1) we will get,


x=(20-4y)/(2)

Substituting this value in equation (2) we will get,


3*(20-4y)/(2)+2y=26


(60-12y)/(2)+2y=26

Let us have a common denominator.


(60-12y)/(2)+(2*2y)/(2)=26


(60-12y)/(2)+(4y)/(2)=26


(60-12y+4y)/(2)=26


(60-8y)/(2)=26


(60-8y)/(2)*2=26*2


60-8y=52


60-60-8y=52-60


-8y=-8

Upon dividing both sides by
-8 we will get,


(-8y)/(-8)=(-8)/(-8)


y=1

Upon substituting
y=1 in equation (1) we will get,


2x+4*1=20


2x+4=20


2x+4-4=20-4


2x=16

Upon dividing both sides of the equation by 2 we will get,


(2x)/(2)=(16)/(2)


x=8

Therefore, the solution of our given system of equations is
(8,1).

User Trantu
by
6.4k points