The answer is: "
3x³ + x² − 2x " .
________________________________________________________Step-by-step explanation:_________________________________________________________Take the first expression; or the "numerator" ;
and "factor out" a: "
6x² " :
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![(18x^5+6x^4-12x^3)/(6 x^(2) ) = (6x^2(3x^3+x^2-2x))/(6x^2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/wrb65le1lrr28mt1ds8z4utzbayrxl6zzt.png)
;
→ Both " 6x² " values "cancel out to 1" ;
→ since: " { 6x² / 6x² = 1 } " ;
And we have: "
3x³ + x² − 2x " .
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