Question

1. Calculate the mass (in grams) of 6.15 moles of the following:

a) P4010
b) AgC2H302
c) Fe(CN)

Answer 1

a. 2683.168 g

b. 2683.168 g

c. 663.468 g

Further explanation

Given

Compounds

Required

The mass

Solution

Mass = mol x MW

a) P4010 (MW=283.9 g mol−1)

mass = 6.15 x 283.9 g mol−1

mass = 1745.985 g

b) AgC2H302 (MW=436.2875 g/mol)

mass = 6.15 x 436.2875 g/mol

mass = 2683.168 g

c) Fe(CN)2 (MW=107.881 g/mol)

mass = 6.15 x 107.881 g/mol

mass = 663.468 g